INDIAN NAVY ENTRANCE TEST REASONING NUMERICAL ABILITY MOCK TEST
INDIAN NAVY ENTRANCE TEST REASONING NUMERICAL ABILITY MOCK TEST
Question – 1 : A sum of Rs. 3200 was to be divided between A,B,C and D in the ratio 4: 6:7:3 . But by mistake, it was divided in the ratio 3: 5: 6: 2 As a result, who got 1623% less than her due?
Answer – (A) : D
Answer – (B) : C
Answer – (C) : D
Answer – (D) : A
View Answer
Correct Answer : (C)
Explanation : Correct ratio of A,B,C and D=4x:6x:7x:3x4x+6x+7x+3x=320020x=3200x=320020=160Share of A=4×160=640Share of B=6×160=960Share of C=7×160=1120Share of D=3×160=480Wrong ratio of A,B,C and D=3x:5x:6x:2x3x+5x+6x+2x=320016x=3200x=320016=200Wrong share of A=3×200=600Wrong share of B=5×200=1000Wrong share of C=6×200=1200Wrong share of D=2×200=400A got less than her due =[(640−600)640]×100=6.25%B got less than her due =[(960−1000)960]×100=4.16%C got less than her due =[(1120−1000)1120]×100=7.14%D got less than her due =[(480−400)480]×100=16%
Question – 2 : Choose the box that is similar to the box formed from the given sheet of paper (x).
Answer – (A) : (1), (2), (3) and (4)
Answer – (B) : (1), (2) and (3) only
Answer – (C) : (2) and (3) only
Answer – (D) : (1), (2), (3) and (4)
View Answer
Correct Answer : (D)
Explanation : The figure (x) is similar to the Form (5). So, when the sheet in figure (x) is folded to form a cube, then the face bearing a dot appears opposite to a blank face, the face bearing a ‘+’ sign appears opposite to another blank face and the face bearing a circle appears opposite to the third blank face. Clearly, all the four cubes shown in figures (1), (2), (3) and (4) can be formed.
Question – 3 : The earth makes a complete rotation about its axis in 24 h. What angle will it turn in 3 h 20 minutes?
Answer – (A) : 50°
Answer – (B) : 50°
Answer – (C) : 120°
Answer – (D) : None of these
View Answer
Correct Answer : (B)
Explanation : Given:Earth makes a complete rotation about its axis in 24 hThere fore in 24 hours angle turned is 360 degrees.ThereforesIn 1 hour angle turned = 360∘24In 3 h 20 minutes angle turned= 360024 × 103= 50°
Question – 4 : In the following question, select the number from the options that will come in place of ‘?’.
Answer – (A) : 84
Answer – (B) : 91
Answer – (C) : 83
Answer – (D) : 95
View Answer
Correct Answer : (A)
Explanation : Given-The pattern followed is-⇒(1×2)+1=3⇒(4×3)+2=14⇒(9×4)+3=39On following the same pattern,⇒(16×5)+4=?⇒80+4=?⇒84=?
Question – 5 : The third proportional of 25 and m is 36. The average of m and 40 is n. Find the fourth proportional to (m + n), (2n – m) and (2m – n).
Answer – (A) : 2m+2n13
Answer – (B) : 22m–n13
Answer – (C) : 4m–2n11
Answer – (D) : 2m+2n13
View Answer
Correct Answer : (D)
Explanation : Given:⇒ 25 ∶ m = m ∶ 36⇒ m = 30Then,⇒ m+402 = n⇒ 30+402 = n⇒ n = 35Given,(m + n) ∶ (2n – m) = (2m – n) ∶ ?⇒ (30 + 35) ∶ (2 × 35 – 30) = (2 × 30 – 35) ∶ ?⇒ 65 ∶ 40 = 25 ∶ ?⇒ ? = 25 × 4065⇒ ? = 20013⇒ ? = 2m+4n13⇒ ? = 2m+2n13
Question – 6 : Direction: A series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series.26, 38, 52, ?
Answer – (A) : 68
Answer – (B) : 68
Answer – (C) : 81
Answer – (D) : 65
View Answer
Correct Answer : (B)
Explanation : Here, the pattern is-26=52+138=62+252=72+368=82+4
Question – 7 : RINDAOYR
Answer – (A) : 6, 8, 4, 2, 3, 5, 1, 7
Answer – (B) : 4, 7, 2, 1, 6, 3, 8, 5
Answer – (C) : 6, 8, 4, 2, 3, 5, 1, 7
Answer – (D) : 5, 8, 2, 1, 7, 3, 6, 4
View Answer
Correct Answer : (C)
Explanation : 68423517ORDINARY‘ORDINARY’ is a meaningful English word.
Question – 8 : If 14,1x and 110 are in HP , then find the value of x .
Answer – (A) : 7
Answer – (B) : 6
Answer – (C) : 7
Answer – (D) : 8
View Answer
Correct Answer : (C)
Explanation : Given,14,1x and 110 are in HPWe know that,If a1,a2,a3,… is AP then 1a1,1a2,1a3,… is HP and vice versa.Therefore,4,x and 10 is in AP .⇒x−4=10−x⇒2x=10+4⇒2x=14⇒x=142⇒x=7
Question – 9 : Arrangement of following fractions in ascending order.13,34,25,67
Answer – (A) : 13,25,34,67
Answer – (B) : 67,25,34,13
Answer – (C) : 13,25,34,67
Answer – (D) : 67,34,25,13
View Answer
Correct Answer : (C)
Explanation : Resolving the fractions:13=0.33334=0.7525=0.4067=0.857Arranging in ascending order,0.333>0.40>0.75>0.857So, the correct sequence will be 13,25,34,67 .
Question – 10 : Which of the following terms follows the trend of the given list?AABAAAA, BAAAAAA, AAAAABA, AAABAAA, ABAAAAA, _______________.
Answer – (A) : AAAAAAB
Answer – (B) : AABAAAA
Answer – (C) : BAAAAAA
Answer – (D) : AAAAAAB
View Answer
Correct Answer : (D)
Explanation : In the given series position of ‘B’ is two step backwards (i.e., second place towards left).AABAAAA → BAAAAAA → AAAAABA → AAABAAA → ABAAAAA → AAAAAABSo, the next term in the series will be ‘AAAAAAB’.
Question – 11 : 4 9 2 3 5 7 8 1 ?
Answer – (A) : 6
Answer – (B) : 6
Answer – (C) : 15
Answer – (D) : 16
View Answer
Correct Answer : (B)
Explanation : The sum of the numbers in each column is 151st column = 4 + 3 + 8 = 152nd column = 9 + 5 + 1 = 15Similarly, the third column = 2 + 7 + ? = 15 or? = 15 – 9= 6
Question – 12 : Convert 58 to decimal.
Answer – (A) : 0.625
Answer – (B) : 0.625
Answer – (C) : 0.875
Answer – (D) : 0.058
View Answer
Correct Answer : (B)
Explanation : As we know,By dividing, we can get the desired decimal.18 = 0.12558 = 18 × 5 = 0.125 × 5 = 0.625∴ Required value = 0.625
Question – 13 : Select the option that can replace the question mark (?) in the following number series.2, 13, 67, ?, 817, 1639, 1645
Answer – (A) : 271
Answer – (B) : 269
Answer – (C) : 230
Answer – (D) : 721
View Answer
Correct Answer : (A)
Explanation : The pattern follows here is:(2 × 6) + 1 = 13(13 × 5) + 2 = 67(67 × 4) + 3 = 271(271 × 3) + 4 = 817(817 × 2) + 5 = 1639(1639 × 1) + 6 = 1645
Question – 14 : If N=23×34×52 , find the total number of even factors of N .
Answer – (A) : 45
Answer – (B) : 45
Answer – (C) : 54
Answer – (D) : 65
View Answer
Correct Answer : (B)
Explanation : Even factors are those which are a multiple of 2.If a number N is expressed in terms of factors such as ax×by×czthen the total number of factors of N=(x+1)×(y+1)×(z+1)Number of factors of the given no. N=(3+1)×(4+1)×(2+1)=60Number of odd factors of the given no. N=(4+1)×(2+1)=15∴ Number of even factors =60−15=45
Question – 15 : The average of seven consecutive odd numbers (in increasing order) is k. If the next four consecutive odd numbers are included, then the average of all the number is:
Answer – (A) : k + 4
Answer – (B) : k + 3
Answer – (C) : k + 4
Answer – (D) : k + 2
View Answer
Correct Answer : (C)
Explanation : Given:The average of seven consecutive odd numbers (in increasing order) is k.Average = Total sumNumber of elementsLet seven consecutive odd numbers be a,a+2,a+4,a+6,a+8,a+10 and a+12Accordingly,a+a+2+a+4+a+6+a+8+a+10+a+12=k×7⇒7a+42=7k⇒a+6=k⇒a=k−6New average =(a+14+a+16+a+18+a+20)+(7a+42)(7+4)=(11a+110)11=a+10∴ New average = k – 6 + 10 = k + 4
Question – 16 : Find the simple interest on Rs.3000 at 254% per annum for the period from 4th February, 2005 to 18th April, 2005 .
Answer – (A) : Rs.37.50
Answer – (B) : Rs.47.50
Answer – (C) : Rs.44.50
Answer – (D) : Rs.50.50
View Answer
Correct Answer : (A)
Explanation : Given-Principal P=Rs.3000Rate R=254% per annumTime T= 4th February, 2005 to 18th April, 2005Number of days =(24+31+18)=73T=73365=15 yearAccording to the formula-SI=P×R×T100 where SI is simple interest⇒SI=3000×254×15100⇒SI=Rs.37.50
Question – 17 : A car travels a distance of 840 km at a uniform speed. If the speed of the car is 10 kmph more, it takes two hours less to cover the same distance. The original speed of the car is:
Answer – (A) : 60 kmph
Answer – (B) : 50 kmph
Answer – (C) : 75 kmph
Answer – (D) : 60 kmph
View Answer
Correct Answer : (D)
Explanation : Let the original speed of the car is x km/hr.Then, time taken in moving 840 km =840x hrIf speed is going 10 km/hr more =x+10Then, time taken in moving 840 km =840x+10 hr∴840x−840x+10=2⇒840(x+10)−840x=2x(x+10)⇒2×2+20x−8400=0⇒x2+70x−60x−4200=0⇒(x+70)(x−60)=0⇒x=60 or x=−70If x=−70 is not true because the speed is not negetive.So, speed is 60 km/hr.
Question – 18 : In a certain code language, ‘CAP’ is written as ‘20’ and ‘ROM’ is written as ‘46’. What will be the code for ‘RUB’ in that code language?
Answer – (A) : 41
Answer – (B) : 41
Answer – (C) : 53
Answer – (D) : 51
View Answer
Correct Answer : (B)
Explanation : As per the English alphabetical series and its place value.The logic followed here is: C A P 3 1 16 CAP → 1 + 3 + 16 = 20 R O M 18 15 13ROM → 18 + 15 + 13 = 46Similarly, R U B 18 21 2RUB → 18 + 21 + 2 = 41
Question – 19 : A and B can do a piece of work in 72 days. B and C in 120 days and A and C in 90 days. In what time can A alone do it?
Answer – (A) : 120 days
Answer – (B) : 55 days
Answer – (C) : 110 days
Answer – (D) : 60 days
View Answer
Correct Answer : (A)
Explanation : We know that,Time taken = 1rate of workTherefore, according to the question,2(1A+1B+1C)=172+1120+1902A+2120=172+1120+1902A=172+190−1120⇒2A=5+4−3360⇒2A=6360⇒1A=1120∴A alone will do that work in 120 days.
Question – 20 : A shopkeeper sold an item at 20% loss after giving a discount equal to half the marked price. Then, the cost price is:
Answer – (A) : 58 th of marked price
Answer – (B) : 414 th of marked price
Answer – (C) : 58 th of marked price
Answer – (D) : 512 th of marked price
View Answer
Correct Answer : (C)
Explanation : Let MP = x∴ Discount = x2∴ SP = MP – Discount = x – x2=x2Now, loss = 20%(SP−CP)CP × 100 = 20Here, M.P = marked price, C.P = cost price, S.P = selling price⇒x2−CPCP=−15⇒x2CP−1=−15⇒x2CP=1−15=45⇒ CP = 5×8=(58) × MP = 58 of MP
Question – 21 : Raj got a new chair for 35% discount. Had Raj got no discount, Raj would have had to pay Rs. 224 more. How much did Raj pay for the chair?
Answer – (A) : Rs. 416
Answer – (B) : Rs. 640
Answer – (C) : Rs. 208
Answer – (D) : Rs. 224
View Answer
Correct Answer : (A)
Explanation : Given:Raj got 35% discountIf there was no discount, Raj would pay Rs. 224This means giving 35% discount = Rs. 224 off∴35% of Marked Price = Rs. 224∴ 35100× Marked price =224∴ Marked Price = Rs. 640∴ Raj paid =640−224= Rs. 416
Question – 22 : The difference between compound interest and simple interest for 2 years on the sum Rs.2900 at a certain rate is Rs.14.21 . What is the annual rate of interest?
Answer – (A) : 7%
Answer – (B) : 10%
Answer – (C) : 8%
Answer – (D) : 11%
View Answer
Correct Answer : (A)
Explanation : Given-Sum P=Rs.2900Time T=2 yearsDifference between compound interest and simple interest d=Rs.14.21According to the formula-d=P×R210000 where R is annual rate of interest⇒14.21=2900×R210000⇒R2=49⇒R=7%
Question – 23 : A rectangular park is to be constructed whose width is less by 3m from its length. It’s area is 4 sq.m. more than the isosceles triangular park already constructed whose base is equal to the width of the rectangular park and height is 12 m. The length of this rectangular park will be
Answer – (A) : 7 m
Answer – (B) : 4 m
Answer – (C) : -1 m
Answer – (D) : 6 m
View Answer
Correct Answer : (A)
Explanation : Length of Rectangular Park =lBreadth of Rectangular Park =l−3Altitude of Triangular Park =12Breadth of Triangular Park =l−3Now,Area of Rectangle =l(l−3)Area of Triangle =12×12(l−3)Area of Rectangle – Area of Triangle = 4⇒l(l−3)−12×12(l−3)=4⇒l2−91+14=0⇒(l−2)(l−7)=0⇒l=2,7Since, breadth is l−3,l≠2∴l=7 m
Question – 24 : In a certain code language, ‘MANGO’ is written as ‘93425’ and GREAT’ is written as ‘28631’. What will be the code for ‘GREEN’ in that code language?
Answer – (A) : 28664
Answer – (B) : 28994
Answer – (C) : 28661
Answer – (D) : 28665
View Answer
Correct Answer : (A)
Explanation : Alphabets are coded as:MANGO93425Code for GREAT,GREAT28631So, code for GREEN is:GREEN28664Thus, ‘28664’ is the answer.
Question – 25 : If goods be purchased for Rs 450 and one-third sold at a loss of 10%. At what gain percent should the remainder be sold so as to gain 20% on the whole transaction.
Answer – (A) : 35%
Answer – (B) : 32%
Answer – (C) : 35%
Answer – (D) : 28%
View Answer
Correct Answer : (C)
Explanation : Given:Total price of the goods = Rs 450∴ Price of one third part of the goods =Rs 4503 = Rs 150And price of remainder part =Rs (450 – 150) = Rs 300∵ One third part is sold with 10% loss∴ Price at which one third part is sold =Rs {150 – (150× 0.10)} = Rs135Let, the remainder part is sold at a gain percentage of x.∴ Price at which the remainder part is sold = Rs 300+300×x100= Rs 3001+x100According to the question,135 + 3001+x100 = 450 + 450 × 20100⇒ 135 + 3001+x100 = 450 + 90⇒ 3001+x100 = 540 – 135⇒ 1+ x100=405300⇒ x100=405300 – 1⇒ x100=105300⇒ x = 1053 = 35